To find the number of excess electrons, we use the formula:
\(n = \frac{|q|}{e}\) where:
- \(q = 3.2 \times 10^{-6} \text{C} \) is the charge on the body,
- \(e = 1.6 \times 10^{-19} \text{C} \) is the charge of one electron.
Substituting the values: \(n = \frac{3.2 \times 10^{-6}}{1.6 \times 10^{-19}} = 3.2 \times 10^{16}\)
Thus, the number of excess electrons is \(( 3.2 \times 10^{16} ).\)
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: 