We are given the charge on the body as \( -3.2 \, \mu C \). The charge of a single electron is \( e = 1.6 \times 10^{-19} \, C \).
The number of excess electrons \( n \) is given by:
\[ n = \frac{\text{Charge}}{\text{Charge of 1 electron}} \]
\[ n = \frac{-3.2 \times 10^{-6}}{1.6 \times 10^{-19}} = 2 \times 10^{13} \]
The number of excess electrons is \( 2 \times 10^{13} \), which corresponds to option (C).