Question:

A body falls freely from the top of a tower. It covers $36\%$ of the total height in the last second before striking the ground level. The height of the tower is

Updated On: Jul 5, 2022
  • 50m
  • 75m
  • 100m
  • 125m
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The Correct Option is D

Solution and Explanation

Let height of tower is h and body takes time t to reach the ground when it falls freely. $\therefore h=\frac{1}{2} g t^{2} \ldots$(i) In last second ie, the sec body travels $=0.36 h$ It means in rest of the time ie, in $(t-1) \sec$ it travels $=h-0.36\, h=0.64\, h$ Now, applying equation of motion for $(t-1) \sec$ $0.64 \,h=\frac{1}{2} g(t-1)^{2} \ldots $ (ii) From Eqs. (i) and (ii), we get $t=5 \,s$ and $h=125\, m$
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The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

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