A body falls freely from a height of 100 m on to the ground and rebounds to a maximum height of 36 m after collision. The coefficient of restitution between the ground and the body is:
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The coefficient of restitution is the square root of the ratio of rebound height to drop height when a body is dropped and rebounds.
The body falls from a height of 100 m and rebounds to a height of 36 m after collision. The coefficient of restitution \( e \) is given by the ratio of the square root of the rebound height to the drop height:
\[
e = \sqrt{\frac{h_{\text{rebound}}}{h_{\text{drop}}}}
\]
Substituting the values:
\[
e = \sqrt{\frac{36}{100}} = \sqrt{0.36} = 0.6
\]
Thus, the coefficient of restitution between the ground and the body is \( 0.6 \).
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Approach Solution -2
Step 1: Understand coefficient of restitution.
The coefficient of restitution \( e \) is the ratio of the speed after collision to the speed before collision (along the line of impact):
\[
e = \sqrt{\frac{\text{height after rebound}}{\text{height before impact}}}
\] Step 2: Substitute the given values.
\[
e = \sqrt{\frac{36}{100}} = \sqrt{0.36} = 0.6
\] Final Answer: \( \boxed{0.6} \)