Question:
A body covers 26, 28, 30, 32 meters in $10^{th}$, $11^{th}$, $12^{th}$ and $13^{th}$ seconds respectively. The body starts
A body covers 26, 28, 30, 32 meters in $10^{th}$, $11^{th}$, $12^{th}$ and $13^{th}$ seconds respectively. The body starts
Updated On: Jul 5, 2022
- from rest and moves with uniform velocity
- from rest and moves with uniform acceleration
- with an initial velocity and moves with uniform acceleration
- with an initial velocity and moves with uniform velocity
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The Correct Option is C
Solution and Explanation
The distance covered in nth second is $S_n = u + \frac{1}{2} (2n - 1)a $
where u is initial velocity & a is acceleration then $26 = u + \frac{19a}{2}$ .....(1)
$28 = u + \frac{21a}{2} $ ....(2)
$30 = u + \frac{23 a}{2}$ .....(3)
$32 = u + \frac{25a}{2}$ ......(4)
From e (1) & (2) we get u = $7 m/ \sec, a = 2 \, m/ \sec^2$
$\therefore$ The body starts with initial velocity u = 7 m/sec
and moves with uniform acceleration $a = 2 m/ \sec^2$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.