A bob is hanging over a pulley inside a car through, a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration '$a$' directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration '$a$' vertically. The tension in the string is equal to -
- $m \sqrt{g^{2} + a^{2}}$
- $m \sqrt{g^{2} + a^{2}} - ma$
- $m \sqrt{g^{2} + a^{2}} + ma$
- $m (g + a)$
The Correct Option is C
Solution and Explanation
$T - m \sqrt{ a ^{2}+ g ^{2}}= ma$
$T = ma + m \sqrt{ a ^{2}+ g ^{2}}$
Top Questions on tension
A body of mass 1kg is suspended with the help of two strings making angles as shown in the figure. Magnitude of tensions $ T_1 $ and $ T_2 $, respectively, are (in N):
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Concepts Used:
Tension
A force working along the length of a medium, especially if this force is carried by a flexible medium like cable or rope is called tension. The flexible cords which bear muscle forces to other parts of the body are called tendons.
Net force = 𝐹𝑛𝑒𝑡 = 𝑇−𝑊=0,
where,
T and W are the magnitudes of the tension and weight and their signs indicate a direction, be up-front positive here.
Read More: Tension Formula