Question:

A block of mass $M$ is pulled along a horizontal frictionless surface by a rope of mass $m$. If a force $P$ is applied at the free end of the rope, the force exerted by the rope on the block is

Updated On: Jun 14, 2022
  • $ \frac{Pm}{M+m} $
  • $ \frac{Pm}{M-m} $
  • $ P $
  • $ \frac{PM}{M+m} $
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The Correct Option is D

Solution and Explanation

Let acceleration of system (rope + block) is an along the direction of applied force. Then $ a=\frac{P}{M+m} $ Draw the FBD of block and rope as shown in figure.where, $ T $ is the required parameter For block $ T=Ma $ $ \Rightarrow $ $ T=\frac{MP}{M+m} $
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