Energy of a photon is given by:
\[
E = \frac{hc}{\lambda}
\]
Where \( h \) is Planck’s constant, \( c \) is the speed of light, and \( \lambda \) is the wavelength.
- Blue light has shorter wavelength than red light, so energy per photon of blue light is greater than that of red light.
- Intensity is the total energy per unit area per unit time. If both beams have the same intensity, then:
\[
\text{Number of photons} = \frac{\text{Total energy}}{\text{Energy per photon}}
\]
- Since red photons have less energy, more of them are required to deliver the same intensity.
Therefore, the red beam has a greater number of photons than the blue beam.
Final answer: The red beam has more number of photons than the blue beam.