The condition for fringe coincidence is:
\[ m_1 \lambda_1 = m_2 \lambda_2 \]
where \(m_1 = 5\), \(m_2 = 4\), and \(\lambda_1 = 520 \, \text{nm}\). Substituting:
\[ 5 \cdot 520 = 4 \cdot \lambda \Rightarrow \lambda = \frac{5 \cdot 520}{4} = 650 \, \text{nm} \]
The value of \(\lambda\) is 650 nm.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?