Question:

A beam of cathode rays is subjected to crossed electric $(E)$ and magnetic fields $(B)$. The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given by (Where $V$ is the potential difference between cathode and anode)

Updated On: Jun 23, 2024
  • $\frac {B^2}{2VE^2}$
  • $\frac {2VB^2}{E^2}$
  • $\frac {2VE^2}{B^2}$
  • $\frac {E^2}{2VB^2}$
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The Correct Option is D

Solution and Explanation

When a beam of cathode rays (or electrons) are subjected to crossed electric $(E)$ and magnetic $(B)$ fields, the beam is not deflected, if

Force on electron due to = Force on electron due magnetic field to electric field Bev = eE
or $v= \frac {E}{B}...(i) $
If $V$ is the potential difference between the anode and the cathode, then
$\therefore \frac {1}{2}mv^2=eV $
$\frac {e}{m}= \frac {v^2}{2V} ...(ii) $
Substituting the value of $v$ from equation (i) in equation (ii), we get
$\frac {e}{m}= \frac {E^2}{2VB^2}$
Specific charge of the cathode rays $\frac {e}{m}= \frac {E^2}{2VB^2}$
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