A bead of mass m is released from rest at A to move along the fixed smooth circular track as shown in figure. The ratio of magnitudes of centripetal force and normal reaction by the track on the bead at any point P0 described by the angle θ ( ≠ 0 ) would
Increase with θ
Decrease with θ
Remain constant
First increase with θ and then decrease
The correct answer is option C) Remain constant
Applying the law of conservation of energy at point P0 we get
1/2 mv2 = mgR sinθ
⇒ mv2 / R = 2mg sinθ
But mv2 / R = centripetal force FC
⇒ FC = 2mg sinθ
Also, N - mg sinθ = FC
⇒ N - mg sinθ = 2mg sinθ
⇒ N = 3mg sinθ
Therefore, the ratio of centripetal force to the normal reaction is given by
FC / N = (2mg sinθ) / (3mg sinθ)
⇒ FC / N = 2/3 that represents a constant value.