Question:

A batsman played n + 2 innings and got out on all occasions. His average score in these n + 2 innings was 29 runs and he scored 38 and 15 runs in the last two innings. The batsman scored less than 38 runs in each of the first n innings. In these n innings, his average score was 30 runs and lowest score was x runs. The smallest possible value of x is

Updated On: Aug 21, 2024
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The Correct Option is A

Solution and Explanation

The correct answer is (A): 22

Total score in (n+2)(n+2) inning = 29×(n+2)29×(n+2)

The total score in n innings = 29(n+2)381529(n+2)-38-15

29n+5=30nn=529n+5=30n ⇒ n=5

Total score in 55 innings = 30×5=150=37×4+230×5=150=37×4+2

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