Question:
A bar magnet is placed upright on a floor (so that the axis of the magnet is vertical). A copper ring is held above the magnet, with its plane horizontal and released. The copper ring falls in such a manner that its axis always coincides with that of the magnet. What will be the acceleration with which the ring will fall?
Acceleration due to gravity is $ 10\,m/s^{2} $ .
A bar magnet is placed upright on a floor (so that the axis of the magnet is vertical). A copper ring is held above the magnet, with its plane horizontal and released. The copper ring falls in such a manner that its axis always coincides with that of the magnet. What will be the acceleration with which the ring will fall?
Acceleration due to gravity is $ 10\,m/s^{2} $ .
Updated On: Jun 3, 2024
- $ 10\,m/s^{2}$
- Less than $ 10\,m/s^{2} $
- More than $ 10\,m/s^{2} $
- the answer will depend upon which pole of the magnet is up
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The Correct Option is B
Solution and Explanation
The acceleration with which the ring will fall will be class than $10\, m / s ^{2}$.
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter