Initial mass of the magnet m1 = m and final mass of the magnet m2 = 4 m.
The time period \(T = 2\pi \sqrt {\frac {I}{MB}}\)
\(T = 2\pi \sqrt {\frac {mk^2}{MB}}\)
⇒ \(T ∝ \sqrt {m}\)
Therefore,
\(\frac {T_1}{T_2} = \sqrt {\frac {m_1}{m_2}}\)
\(\frac {T_1}{T_2} = \sqrt {\frac {m}{4m}}\)
\(\frac {T_1}{T_2} = \frac 12\)
\(T_2 = 2T_1\)
\(T_2 = 2T\)
So, the correct option is (B): Motion remains S.H. with time period = 2T
A current-carrying coil is placed in an external uniform magnetic field. The coil is free to turn in the magnetic field. What is the net force acting on the coil? Obtain the orientation of the coil in stable equilibrium. Show that in this orientation the flux of the total field (field produced by the loop + external field) through the coil is maximum.
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The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
The Earth's magnetic field stretches millions of kilometers into space and resembles a bar magnet. The earth's magnetic pole is positioned between the Northern Pole and the North Pole's Antarctic magnets. That is why a compass magnet's north pole points north (north and south poles attract).
The Earth's magnetic field extends far and wide, but it is very small in terms of field power. It has a field power of merely 40,000 nT as compared to a refrigerator magnet which has a power of 107 nT.
These are the components that are responsible for the magnitude and direction of the magnetic field of the earth at a given location: