Step 1: In an oblique collision of identical masses where both move at the same angle $\theta$ to the original path, the situation is symmetrical.
Step 2: Conservation of momentum perpendicular to the original direction: $m v_1 \sin 30^\circ - m v_2 \sin 30^\circ = 0$.
Step 3: This directly implies $v_1 = v_2$.
Step 4: Therefore, the ratio $v_1 : v_2$ is $1 : 1$. Thus, $x = 1$.