Question:

A ball rolls up a slope. At the end of three seconds its velocity is 20 cm/s, at the end of eight seconds its velocity is 0. What is the average acceleration from the third to the eighth second?

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Remember that average acceleration is the change in velocity divided by the change in time, and it can be negative if the object is decelerating.
Updated On: Mar 30, 2025
  • 2.5 cm/s²
  • 4.0 cm/s²
  • 5.0 cm/s²
  • 6.0 cm/s²
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The Correct Option is B

Solution and Explanation


The average acceleration is given by: \[ a = \frac{v_f - v_i}{t_f - t_i} \] where \( v_f = 0 \), \( v_i = 20 \, \text{cm/s} \), \( t_f = 8 \, \text{s} \), and \( t_i = 3 \, \text{s} \). Thus: \[ a = \frac{0 - 20}{8 - 3} = \frac{-20}{5} = -4 \, \text{cm/s}^2 \] So the average acceleration is \( 4.0 \, \text{cm/s}^2 \) in the opposite direction.
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