A ball of mass (m) 0.5 kg is attached to the end of a string having length (l) 0.5 m. The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is 324 N. The maximum possible value of angular velocity of ball (in rad/s) is
- 9
- 18
- 27
- 36
The Correct Option is D
Solution and Explanation
$T \sin \theta$ component will provide necessary centripetal force to the ball towards centre $C$
$\therefore\, T \sin \theta =mr \omega^2=m(l \sin \theta)\omega^2\, $ or $T=m l \omega^2$
$\therefore 15mm \omega=\sqrt{\frac{T}{ml}}$
or $15mm \omega_{max}=\sqrt{\frac{T_{max}}{ml}}=\sqrt{\frac{324}{0.5\times 0.5}}$
$25mm = 36\, rad/s $
$\therefore $ Correct option is (d)
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Concepts Used:
Laws of Motion
The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. They were first disclosed by English physicist and mathematician Isaac Newton.
Newton’s First Law of Motion
Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.
Newton’s Second Law of Motion
Newton's 2nd law of motion deals with the relation between force and acceleration. According to the second law of motion, the acceleration of an object as built by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Newton’s Third Law of Motion
Newton's 3rd law of motion states when a body applies a force on another body that there is an equal and opposite reaction for every action.