A ball of mass 0.5 kg is dropped from the height of 10 m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ___ m.
[Use g = 10 m/s2]
[Use g = 10 m/s2]
Correct Answer: 5
Solution and Explanation
\(⇒ t = 1 sec\)
\(\Delta h = \frac{1}{2}gt^2 = \frac{1}{2} \times 5 \times 12^2 = 5 \, \text{m}\)
\(∴\) \(h = H – Δh \)
\(= 10 – 5 = 5 m\)
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].