Question

A ball is thrown vertically upward with a velocity of 20 m/s. What is the maximum height reached by the ball? (Take \( g = 10 \, m/s^2 \))

• A. 40 m
• B. 30 m
• C. 20 m
• D. 50 m

Hint:

For vertical projectile motion, maximum height is calculated by \( H = \frac{u^2}{2g} \), where \(u\) is the initial velocity and \(g\) is acceleration due to gravity.

Answer 1

The Correct Option is C

Step 1: Use the formula for maximum height in vertical motion: \[ H = \frac{u^2}{2g} \] where \( u = 20 \, m/s \) and \( g = 10 \, m/s^2 \). 
Step 2: Substitute the values: \[ H = \frac{20^2}{2 \times 10} = \frac{400}{20} = 20 \, m. \] 
Step 3: Therefore, the maximum height reached by the ball is 20 meters.