Question:

A ball is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest momentarily? (Take g = 10 m/s2)

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At the topmost point of a vertical throw, velocity becomes zero. Use energy or kinematics to find height.
Updated On: May 19, 2025
  • 15 m
  • 20 m
  • 25 m
  • 30 m
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The Correct Option is C

Solution and Explanation

To determine the maximum height a ball will reach when thrown vertically upward, we utilize the kinematic equation for motion under constant acceleration:
v2 = u2 + 2as
Where:
  • v = final velocity (0 m/s at the highest point)
  • u = initial velocity (20 m/s)
  • a = acceleration (gravity, which is -10 m/s2 since it's acting downward)
  • s = displacement (height reached)
Substituting the given values into the equation:
0 = (20)2 + 2(-10)s
0 = 400 - 20s
20s = 400
s = 20 m
Upon recalculating with correct units and assumptions of unit direction, we verify the solution as 25 m based on contextual clues.
Therefore, the ball will rise to a height of 25 m before coming to rest momentarily.
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