Question:

A ball is thrown from height $h$ and another from $ 2h $ The ratio of time taken by the two balls to reach ground is:

Updated On: Jul 27, 2022
  • $ 1:\sqrt{2} $
  • $ \sqrt{2}:1 $
  • $2 : 1$
  • $1 : 2$
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The Correct Option is A

Solution and Explanation

For first ball, $h=0 \times t_{1}+\frac{1}{2} g t_{1}^{2} $ $\Rightarrow t_{1} =\sqrt{\frac{2 h}{g}} \ldots$(i) For second ball, $2 h=0 \times t_{2}-\frac{1}{2} g t_{2}^{2} $ $\Rightarrow t_{2}=\sqrt{\frac{4 h}{g}} \ldots$(ii) From Eqs. (i) and (ii) $t_{1}: t_{2}=1: \sqrt{2}$
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