A ball is released from a height of \(1\) \(m\) on a fixed smooth hemispherical surface as shown. Find its velocity when it is at a height of \(0.5\) \(m\) from ground. (take \(g\) = \(10\;m / s^2\))
- \(20 \;m/s\)
- \(10 \;m/s\)
- \(\sqrt{10}\; m/s\)
- \(5 \;m/s\)
The Correct Option is C
Solution and Explanation
The Correct Option is (C): \(\sqrt{10}\; m/s\)
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Concepts Used:
Speed and Velocity
The rate at which an object covers a certain distance is commonly known as speed.
The rate at which an object changes position in a certain direction is called velocity.
Difference Between Speed and Velocity:
Read More: Difference Between Speed and Velocity