Question:

A ball is released from a height of \(1\) \(m\) on a fixed smooth hemispherical surface as shown. Find its velocity when it is at a height of \(0.5\) \(m\) from ground. (take \(g\) = \(10\;m / s^2\))
A ball is released from a height of 1 m

Updated On: Aug 17, 2024
  • \(20 \;m/s\)
  • \(10 \;m/s\)
  • \(\sqrt{10}\; m/s\)
  • \(5 \;m/s\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

The Correct Option is (C): \(\sqrt{10}\; m/s\)

Was this answer helpful?
1
0

Questions Asked in JEE Main exam

View More Questions

Concepts Used:

Speed and Velocity

The rate at which an object covers a certain distance is commonly known as speed.

The rate at which an object changes position in a certain direction is called velocity.

Difference Between Speed and Velocity:

Difference Between Speed and Velocity

Read More: Difference Between Speed and Velocity