Question:
A ball is projected horizontally with a velocity of $4\,m s^{-1}$ from the top of a tower. The velocity of the ball after 0.7 s is (Take g = 10 $m s^{-2}$)
A ball is projected horizontally with a velocity of $4\,m s^{-1}$ from the top of a tower. The velocity of the ball after 0.7 s is (Take g = 10 $m s^{-2}$)
Updated On: Jun 20, 2022
- $1\,ms^{-1}$
- $10\, ms^{-1}$
- $8\,ms^{-1}$
- $3 \,ms^{-1}$
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The Correct Option is C
Solution and Explanation
Velocity of the ball after time t
$=\sqrt{v^2_x+v^2_y}$
$=\sqrt{(4)^2+(gt)^2}$
$=\sqrt{16+(10 \times 0.6)^2}$
= $8 ms^{-1}$
$=\sqrt{v^2_x+v^2_y}$
$=\sqrt{(4)^2+(gt)^2}$
$=\sqrt{16+(10 \times 0.6)^2}$
= $8 ms^{-1}$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.