Question

A bag contains 6 red, 4 blue and 10 white balls. A ball is picked from the bag at random What is the probability that it is neither white nor blue?

• A. \(\frac {20}{6}\)
• B. \(\frac {3}{10}\)
• C. \(\frac {2}{5}\)
• D. \(\frac {1}{2}\)

Answer 1

The Correct Option is B

To find the probability that a randomly picked ball is neither white nor blue, we need to determine the favorable outcomes and the total possible outcomes. The bag contains:

• 6 red balls
• 4 blue balls
• 10 white balls

Total number of balls in the bag:

6 + 4 + 10 = 20

Since we are looking for the probability of picking a ball that is neither white nor blue, we focus on the red balls. The number of red balls is:

6

Thus, the probability of picking a red ball, which is neither white nor blue, is given by the number of red balls divided by the total number of balls:

\(\frac{6}{20}\)

We simplify this fraction:

\(\frac{6}{20} = \frac{3}{10}\)

Therefore, the probability that a randomly picked ball is neither white nor blue is \(\frac{3}{10}\).