Question

A bag contains 5 yellow, 3 green, 2 blue and 7 white balls. If 4 balls are chosen at random, then the probability that none of them are white is

• A. \(\frac{3}{37}\)
• B. \(\frac{7}{34}\)
• C. \(\frac{5}{34}\)
• D. \(\frac{5}{37}\)
• E. \(\frac{3}{34}\)

Answer 1

Answer: (E)

The correct option is (E): \(\frac{3}{34}\)