Question

A bag contains 5 red balls, 7 green balls, and 8 blue balls. One ball is drawn at random. What is the probability that the ball is either red or green?

• A. \( \frac{5}{20} \)
• B. \( \frac{7}{20} \)
• C. \( \frac{12}{20} \)
• D. \( \frac{5}{10} \)

Hint:

Remember: To calculate probability, divide the number of favorable outcomes by the total number of outcomes.

Answer 1

The Correct Option is C

Given: The total number of balls in the bag is: \[ 5 \text{ red balls} + 7 \text{ green balls} + 8 \text{ blue balls} = 20 \text{ balls} \] Step 1: Calculate favorable outcomes The favorable outcomes are drawing either a red or green ball. The total number of favorable outcomes is: \[ 5 \text{ red balls} + 7 \text{ green balls} = 12 \text{ favorable outcomes} \] Step 2: Calculate the probability The probability of drawing a red or green ball is: \[ P(\text{red or green}) = \frac{12}{20} = \frac{3}{5} \] Answer: The correct answer is option (3): \( \frac{12}{20} \).