Question

Who is the eldest brother?

• A. A
• B. E
• C. C
• D. Cannot be determined
• A. B
• B. D
• C. F
• D. Cannot be determined
• A. D and G
• B. E and C
• C. A and B
• D. Cannot be determined
• A. G has 4 elder brothers.
• B. A is older than G but younger than E.
• C. B has three elder brothers.
• D. There is a pair of twins among the brothers.

Answer 1

The Correct Option is B

Let us carefully decode the puzzle step-by-step, keeping track of the logic in terms of age order.
We have seven brothers: A, B, C, D, E, F, and G.
From A’s statement to B: “You are as old as C was when I was twice as old as D” — This gives us a relative age relation:
- There was a past time when A was twice as old as D. At that time, C’s age is equal to B’s current age. This suggests C is older than B, because C’s past age = B’s present age. Therefore, $C>B$.
“And will be as old as E was when he was as old as C is now” — This implies:
- In the future, B will have the same age as E had at a time in the past when E’s age matched C’s current age.
This suggests $E>C$, because E reached C’s current age earlier.
From B’s reply to A: “You may be older than F but G is as old as I was when you were as old as G is” — This gives another chain:
- G’s current age = B’s past age (when A’s age was equal to G’s current age). This indicates $A>G$ and $G>F$.
“And D will be as old as F was when F will be as old as G is” — This is a complex future-past mapping:
- At a future point when F reaches G’s current age, D will match F’s past age. This generally implies $F>D$.
Compiling the deductions: 1. $E>C>B$ (Eldest in this chain)
2. $A>G>F>D$ (Another chain)
3. Since $E>C$ and A is not linked as younger than E, we compare both chains. From hints, $E$ is the eldest overall.
Hence, E is the eldest brother.
\(\boxed{\text{Correct Answer: (B) E}}\)

Answer 2

From the earlier deductions: - $D<F$ (from B’s statement: “D will be as old as F was...”)
- $F<G$ (from A’s remark: “You may be older than F but G is as old as I was...”).
- $G<A$ but $G>F$.
- $B<C$ and $C<E$, but no direct evidence that B is younger than D.
If we compare: $D<F<G<A$ and also $B<C<E$.
Now, comparing the two chains, the youngest is $D$, because all other members are placed above him in age order.
\(\boxed{\text{Correct Answer: (B) D}}\)

Answer 3

Twins have the same age at the current time. In reasoning puzzles, when two members share a relation where their present ages cannot be distinguished (both appear in positions with identical age gaps to others), they are potential twins.
From the given statements, E and C appear in multiple age equality situations: - B will be as old as E was when E was as old as C is now. This unusual symmetry often hints at equal current ages.
- Both E and C are on the same side of the elder chain above B, with no other constraints between them.
Thus, $E$ and $C$ are the most probable twins.
\(\boxed{\text{Correct Answer: (B) E and C}}\)

Answer 4

Let’s check each option using our deduced order: Possible order: $E = C$ (twins), $A$, $G$, $F$, $B$, $D$.
(A) G has 4 elder brothers: Elder than G are $E$, $C$, and $A$ — that’s only 3 elder brothers, so this might already be questionable. However, without a full certainty, we keep checking.
(B) $A>G$ but $A<E$: From our chain, $E>C>B$ and $A>G$, but we never established $E>A$. Hence this statement cannot be confirmed and is therefore false in certainty sense.
(C) B has three elder brothers: Above B are $E$, $C$, and $A$ — correct.
(D) There is a pair of twins: Yes, $E$ and $C$.
Hence, (B) is the false one.
\(\boxed{\text{Correct Answer: (B)}}\)