Let the initial investments of A, B, and C be \(3x\), \(5x\), and \(7x\) respectively.
Step 1: Investments after the changes.
After 1 year, the investments of A, B, and C change. C invests ₹ 33760 more, and A withdraws ₹ 4560. So, their new investments are:
A's new investment = \(3x - 4560\)
B's new investment = \(5x\) (no change)
C's new investment = \(7x + 33760\)
The new ratio of investments is given as 24:59:167. So, we can write the equations:
\[
\frac{3x - 4560}{24} = \frac{5x}{59} = \frac{7x + 33760}{167}.
\]
Step 2: Solve for \(x\).
We now solve the equation for \(x\). Start with the first equation:
\[
\frac{3x - 4560}{24} = \frac{5x}{59}.
\]
Cross multiply:
\[
59(3x - 4560) = 24(5x).
\]
Simplify:
\[
177x - 269640 = 120x.
\]
\[
57x = 269640.
\]
\[
x = \frac{269640}{57} = 4732.63.
\]
Step 3: Find B's investment.
Now that we know \(x\), B's initial investment is \(5x\):
\[
B's \, \text{investment} = 5 \times 4732.63 = 23663.15.
\]
Since the options are rounded to the nearest ₹ 100, the closest answer is ₹ 23,600.