Question:

A 5 A fuse wire can withstand a maximum power of 1 W in circuit. The resistance of the fuse wire is

Updated On: Jul 5, 2022
  • 0.2 $\Omega $
  • 5 $\Omega $
  • 0.4 $\Omega $
  • 0.04 $\Omega $
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The Correct Option is D

Solution and Explanation

Power $\hspace5mm P=i^2R $ $\Rightarrow \hspace5mm R= \frac {P}{i^2} $ Given, P = IW and i = 5A $\therefore \hspace5mm R=\frac {1}{(5)^2}=0.04 \Omega$
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter