A √(34) m long ladder weighing 10 kg leans on a frictionless wall. Its feet rest on the floor 3 m away from the wall as shown in the figure. If Ff and Fw are the reaction forces of the floor and the wall, then ratio of Fw/Ff will be: (Use g = 10 m/s2)
The correct answer is (C) : \(\frac{3}{\sqrt{109}}\)
Fig.
Taking torque from B \(F_w×5=\frac{3}{2}mg\) \(⇒F_w=\frac{3}{10}×10×10\) = 30 N N = mg = 100 N and fr = Fw = 30 N so \(F_f=\sqrt{N^2+f_{r}^{2}}=\sqrt{10900}=10\sqrt{109}\) N therefore , \(\frac{F_w}{F_f}=\frac{3}{\sqrt{109}}\)
Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.
Newton’s Second Law of Motion:
Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.
Mathematically, we express the second law of motion as follows:
Newton’s Third Law of Motion:
Newton’s 3rd law states that there is an equal and opposite reaction for every action.
