$ F \times t = \Delta p = 2 \, m \upsilon \, \cos \, \theta$
($\therefore$ sin components concel out )
$\therefore\:\:\: F = \frac{2 m \upsilon \, cos \, \theta }{t} = \frac{2 \times 3 \times 10 \, cos \,60^\circ}{0.2} = \frac{6 \times 10 \times 0.5}{0.2} $ = 150 $\sqrt {3}$ N