Question:

A 10½ digit Counter-timer is set in the 'frequency mode' of operation (with \( T_s = 1 \, \text{s} \)). For a specific input, the reading obtained is 1000. Without disconnecting this input, the Counter-timer is changed to operate in the 'Period mode' and the range selected is microseconds (\( \mu s \), with \( f_s = 1 \, \text{MHz} \)). The counter will then display

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In frequency mode, the counter measures the frequency of the input signal. In period mode, it measures the inverse of the frequency, i.e., the period.
Updated On: Jan 8, 2026
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The Correct Option is D

Solution and Explanation

In the frequency mode, the counter measures the frequency of a signal. For an input that yields a reading of 1000, the counter is measuring the frequency as: \[ f = \frac{1}{T} \text{where} T = 1 \, \text{s}. \] In period mode, the counter measures the period of the signal. The period is the inverse of the frequency. Since the counter is now set to measure in microseconds (\( \mu s \)) and the frequency has been measured as 1 Hz, the period will be 1 second, which is equivalent to 1000 microseconds. Thus, in period mode, the counter will display 1000. Final Answer: 1000
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