Question:

$ A\,\,0.5\,\,g/L $ solution of glucose is found to be isotonic with a $ 2.5\,\,g/L $ solution of an organic compound. What will be the molecular weight of that organic compound?

Updated On: Jul 28, 2022
  • $ 300 $
  • $ 600 $
  • $ 900 $
  • $ 200 $
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The Correct Option is C

Solution and Explanation

Molarity of glucose solution $ =\frac{0.5\,\,g}{180\times 1L}=0.00277\,\,M $ Isotonic solution have equal molar concentrations, hence molarity of organic compound solution $ =0.00277\,\,M $ $ \therefore $ Molecular weight of compound $ =\frac{2.5}{0.00277\times 1}=900 $
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Concepts Used:

Concentration of Solutions

It is the amount of solute present in one liter of solution.

Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.

Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).

Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage

Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.

Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.

Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.

Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.

Formality - It is the number of gram formula present in one litre of solution.