Question:

A 0.1 molal aqueous solution of a weak acid is 30% ionized. If KfK_f for water is 1.86C/m 1.86^{\circ} C/m, the freezing point of the solution will be -

Updated On: Jul 19, 2024
  • 0.24C-0.24^{\circ} C
  • 0.18C-0.18^{\circ} C
  • 0.54C-0.54^{\circ} C
  • 0.36C-0.36^{\circ} C
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The Correct Option is A

Solution and Explanation

i=1α+nαi = 1 - \alpha + n\alpha
i=10.3+2(0.3) i = 1 - 0.3 + 2 (0.3)
i=1.3i = 1.3
ΔTf=iKfm \Delta T_f = iK_f m
=1.3×1.86×0.1 = 1.3 \times 1.86 \times 0.1
ΔTf=+0.24C\Delta T_f = + 0.24^{\circ} C
Freezing point of solution = - 0.24�C
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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.