Question

500 mL of nitrogen at $27^\circ C$ is cooled to $-5^\circ C$ at the same pressure. The new volume becomes

• A. 326.32 mL
• B. 446.66 mL
• C. 546.32 mL
• D. 771.56mL

Answer 1

The Correct Option is B

Initial volume, \(V_1 = 500 mL\) 
Initial temperature, 
\(T_1 = 27^\circ C = 27 + 273 = 300 K\) 
Final temperature, 
\(T_2 = - 5 + 273 = 268 K\)
\(V_2=?\)
\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)

\(V_2=\frac{V_1 T_2}{T_1}\)

\(V_2=\frac{500\times268}{300}\)
\(V_2=446.66\ mL\)

So, the correct option is (B): 446.66 mL