Question:
5.0 mL of [AgI] / Ag$^+$ sol is coagulated by the addition of 15 mL of 0.001 M potassium iodide solution. The flocculation value of potassium iodide is
5.0 mL of [AgI] / Ag$^+$ sol is coagulated by the addition of 15 mL of 0.001 M potassium iodide solution. The flocculation value of potassium iodide is
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Use the formula: Flocculation value = (millimoles of electrolyte added)/(volume of sol in mL).
Updated On: May 12, 2025
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The Correct Option is C
Solution and Explanation
Flocculation value = $\dfrac{\text{millimoles of electrolyte}}{\text{volume of sol in mL}}$
Millimoles of KI = $15 \times 0.001 = 0.015$ mmol
Flocculation value = $\dfrac{0.015}{5} = 0.003$ mol/L or 3 mmol/L
Millimoles of KI = $15 \times 0.001 = 0.015$ mmol
Flocculation value = $\dfrac{0.015}{5} = 0.003$ mol/L or 3 mmol/L
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