Question:

3 Idiots was screened on which day?

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When you have two “immediately-after” pairs, place the pairs first under any day restrictions (not first/last). Then apply spacing clues like “one movie between X and Y” to eliminate impossible placements.
Updated On: Aug 18, 2025
  • Friday
  • Tuesday
  • Thursday
  • Monday
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The Correct Option is D

Solution and Explanation


Given (from the directions for Q98--100):
Movies: Do Bigha Jameen (DBJ), Sholay (S), 3 Idiots (3I), Chak De (C), Anand (A). Days: Mon--Fri.
(i) S is immediately after DBJ - the pair \fbox{DBJ, S} occupies consecutive days.
(ii) C is immediately followed by A - the pair \fbox{C, A} occupies consecutive days.
(iii) DBJ and C are not on Monday or Friday.
(iv) Exactly one movie between S and 3I. (So their positions differ by 2.)
Step 1: Place \fbox{DBJ, S.}
Because DBJ cannot be Monday or Friday, the only possible consecutive slots are: \fbox{Tue, Wed} or \fbox{Wed, Thu}.
Case A: \fbox{DBJ, S} \(=\) \fbox{Tue, Wed}. Then \(S=\) Wed. Condition (iv) forces 3I on \(\{\)Mon, Fri\(\}\).
\quad\(-\) If \(3I=\) Fri, then \fbox{C, A} must occupy \(\{\)Mon,Tue\(\}\) or \(\{\)Thu,Fri\(\}\). Both impossible since \(C\) cannot be Mon or Fri.
\quad\(-\) If \(3I=\) Mon, the remaining two days (Thu, Fri) must host \fbox{C, A}. Since \(C\) cannot be Fri, we get \(C=\) Thu, \(A=\) Fri.
This satisfies all constraints. So the full schedule is:
\[ \boxed{\text{Mon }3I,\ \text{Tue }DBJ,\ \text{Wed }S,\ \text{Thu }C,\ \text{Fri }A }. \] Case B: \fbox{DBJ, S} \(=\) \fbox{Wed, Thu}. Then \(S=\) Thu. By (iv), 3I must be Tue (one between is Wed) or Sat (not allowed). If \(3I=\) Tue, the pair \fbox{C, A} would have to use Mon and Fri, but \(C\) cannot be Mon or Fri. \(\Rightarrow\) Case B impossible.
Conclusion: The only consistent arrangement puts \(3\) Idiots on \(\boxed{\text{Monday}}\).
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