Question:
3 blue balls and 4 yellow balls are in a box. 3 balls are drawn at random. Let variance and mean be X & Y respectively then value of 3X + 4Y is:
3 blue balls and 4 yellow balls are in a box. 3 balls are drawn at random. Let variance and mean be X & Y respectively then value of 3X + 4Y is:
Updated On: Apr 10, 2024
- 5.21
- 8.39
- 7.34
- 6.54
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The Correct Option is C
Solution and Explanation
The Correct answer is option is (C) : 7.34
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