Question:
\(^{290}_{82}X\stackrel{\alpha}{\rightarrow}Y\stackrel{e^+}{\rightarrow}Z\stackrel{\beta^-}{\rightarrow}P\stackrel{e^-}{\rightarrow}Q\)
In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are :
\(^{290}_{82}X\stackrel{\alpha}{\rightarrow}Y\stackrel{e^+}{\rightarrow}Z\stackrel{\beta^-}{\rightarrow}P\stackrel{e^-}{\rightarrow}Q\)
In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are :
In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are :
Updated On: Dec 4, 2024
- 280, 81
- 286, 80
- 288, 82
- 286, 81
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The Correct Option is D
Solution and Explanation
- After $\alpha$ decay, mass number reduces by 4, atomic number by 2: 286, 80.
- After $\beta^+$ emission, atomic number reduces by 1: 286, 79.
- After $\beta^-$ emission, atomic number increases by 1: 286, 80.
- After electron capture, atomic number reduces by 1: 286, 81.
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