Question:

20 guests have to sit half on each side of a long table. Three particular guests desire to sit on a particular side, five others on the other side. In how many ways, the seating arrangement can be made?

Updated On: Sep 2, 2024
  • \(10!\times\frac{10!}{7!}\times\frac{10!}{5!}\)
  • \(12!\times\frac{10!}{7!}\times\frac{10!}{5!}\)
  • 20!×13!×15!
  • \(20!\times\frac{7!}{3!}\)
  • \(20!\times\frac{10!}{7!}\)
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The Correct Option is B

Solution and Explanation

The correct option is (B): \(12!\times\frac{10!}{7!}\times\frac{10!}{5!}\)
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