Question:

Find out the angle of refraction in a medium of refractive index \(\sqrt{3}\), when the angle of incidence is \(60^\circ\). 
 

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Snell's law helps calculate refraction at the boundary between two media of different refractive indices.
Updated On: Mar 4, 2025
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Solution and Explanation

Using Snell's law: \[ n_1 \sin i = n_2 \sin r, \] where \( n_1 = 1 \) (air), \( n_2 = \sqrt{3} \), \( i = 60^\circ \): \[ \sin r = \frac{n_1 \sin i}{n_2} = \frac{1 \times \sin 60^\circ}{\sqrt{3}} = \frac{\sqrt{3}/2}{\sqrt{3}} = \frac{1}{2}. \] Thus, \( r = 30^\circ \).
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