First, let's determine the total number of electrons in the given electronic configuration: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6$
Total electrons = 2 + 2 + 6 + 2 + 6 = 18 electrons
(1) $\text{P}^{3-}$: Phosphorus (P) has an atomic number of 15, so it has 15 electrons. $\text{P}^{3-}$ gains 3 electrons, resulting in 15 + 3 = 18 electrons.
(2) $\text{Cl}^{-}$: Chlorine (Cl) has an atomic number of 17, so it has 17 electrons. $\text{Cl}^{-}$ gains 1 electron, resulting in 17 + 1 = 18 electrons.
(3) $\text{S}^{2-}$: Sulfur (S) has an atomic number of 16, so it has 16 electrons. $\text{S}^{2-}$ gains 2 electrons, resulting in 16 + 2 = 18 electrons. Because the configuration given is $1s^2, 2s^2, 2p, 3s^2, 3p$,
The configuration of the options, is none of them.