Question:

$(17+16\% \space of \space 200)$ $- (3\% \space of \space 300) =x.$ Find the value of $x ?$

Updated On: Oct 14, 2024

80
88
98
40

Hide Solution

Verified By Collegedunia

The Correct Option is D

Solution and Explanation

$x=(17+16\%of200)−(3\%of300)$
$16\%of200=32$
$32+17=49$
$3\%of300=9$
$49-9=40$
$\therefore x=40$
The correct answer is (D): 40

Was this answer helpful?

0

0

Top Questions on Number Systems

The number of natural numbers, between 212 and 999, such that the sum of their digits is 15, is _____.
- JEE Main - 2025
- Mathematics
- Number Systems
View Solution
The greatest value of $n$ , where $n \in \mathbb{N}$ , such that $3^n$ divides $50!$ is:
- JEE Main - 2025
- Mathematics
- Number Systems
View Solution
Let $A = \{1, 2, 3, \dots, 10\}$ and $B = \left\{ \frac{m}{n} : m, n \in A, m <n \text{ and } \gcd(m, n) = 1 \right\}$ . Then $n(B)$ is equal to :
- JEE Main - 2025
- Mathematics
- Number Systems
View Solution
The remainder, when $7^{98}$ is divided by 23, is equal to:
- JEE Main - 2025
- Mathematics
- Number Systems
View Solution
If $\frac{1}{q + r}, \frac{1}{r + p}, \frac{1}{p + q}$ are in A.P., then:
- VITEEE - 2024
- Mathematics
- Number Systems
View Solution

View More Questions

Questions Asked in KMAT KERALA exam

View More Questions