Question:
$10\, mL$ of $2(M)$ $NaOH$ solution is added to $200\, mL$ of $0.5 (M)$ of $NaOH$ solution. What is the final concentration ?
$10\, mL$ of $2(M)$ $NaOH$ solution is added to $200\, mL$ of $0.5 (M)$ of $NaOH$ solution. What is the final concentration ?
Updated On: Jul 29, 2024
- 0.57 (M)
- 5.7 (M)
- 11.4 (M)
- 1.14 (M)
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The Correct Option is A
Solution and Explanation
From molarity equation
$M_{1} V_{1}+M_{2} V_{2} =MV_{\left(total\right)}$
$2\times\frac{10}{1000}+0.5\times\frac{200}{1000}=M \times\frac{210}{1000}$
$120=M \times210$
$M=\frac{120}{210}=0.57 M$
$M_{1} V_{1}+M_{2} V_{2} =MV_{\left(total\right)}$
$2\times\frac{10}{1000}+0.5\times\frac{200}{1000}=M \times\frac{210}{1000}$
$120=M \times210$
$M=\frac{120}{210}=0.57 M$
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Chemistry is a vast subject and for understanding its significance we can take help of following points:
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Classification of Matter
There are two ways of classifying the matter:
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Matter can exist in three physical states:
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(B) Chemical Classification:
Based upon the composition, matter can be divided into two main types:
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