Question:

10.6 g of a substance of a molecular weight 106 was dissolved in 100 mL of this solution 10 mL of this solution was pipetted out in to a 1000 mLflask and made upto the mark with distilled water.The molarity of the resulting solution is

Updated On: Jun 23, 2023
  • 1 0 M
  • $10^{-2}$M
  • $10^{-3}$M
  • $10^{-4}$m
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The Correct Option is B

Solution and Explanation

Initial molarity- $=\frac{10.6}{106} \times \frac{1000}{ V ( ml )} $ $=\frac{10.6}{106} \times \frac{1000}{100}=1 M$ Now, $M _{1} V _{1}= M _{2} V _{2}$ $1 \times 10= M _{2} \times 1000$ $M _{2}=\frac{10}{1000}$ $M _{2}=10^{-2} M$
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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.