Question:
1 M and 2.5 litre NaOH solution mixed with another 0.5 M and 3 litre NaOH solution. Then find out molarity of resultant solution
1 M and 2.5 litre NaOH solution mixed with another 0.5 M and 3 litre NaOH solution. Then find out molarity of resultant solution
Updated On: Apr 12, 2024
- 0.80 M
- 1.0 M
- 0.73 M
- 0.50 M
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The Correct Option is C
Solution and Explanation
The correct option is (C) : 0.73 M
Mole of 2.5 L of 1M NaOH =2.5×1=2.5
Mole of 3.0 L of 0.5 M NaOH =3.0×0.5=1.5
Total moles of NaOH in solution =2.5+1.5=4.0 (Total volume of solution =2.5+3.0=5.5L)
Thus, M1 ×V1=M2 ×V2 4.0=M2 ×5.5 Molarity of resultant solution = M2 = \(\frac{4.0}{5.5}\) =0.73M
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.