Question:
$1\, M$ and $2.5\,L\,NaOH$ solution mixed with another $0.5\,M$ and $ 3\,L\,NaOH$ solution. Then find out molarity of resultant solution
$1\, M$ and $2.5\,L\,NaOH$ solution mixed with another $0.5\,M$ and $ 3\,L\,NaOH$ solution. Then find out molarity of resultant solution
Updated On: Jun 23, 2023
- 0.80 M
- 1.0 M
- 0.73 M
- 0.50 M
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The Correct Option is C
Solution and Explanation
Moles of $2.5\, L$ of $1\, M\, NaOH =2.5 \times 1=2.5$
Moles of $3.0\, L$ of $0.5\, M\, NaOH =3.0 \times 0.5=1.5$
Total moles of $NaOH$ in solution $=2.5+1.5=4.0$
(Total volume of solution $=2.5+3.0=5.5 L$ )
Thus
$M_{1} \times V_{1}=M_{2} \times V_{2}$
$4.0=M_{2} \times 5.5$
$\therefore$ molarity of resultant solution $=M_{2}=\frac{4.0}{5.5} M$
$\approx 0.73\, M$
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.