Convert to polar form:
\[
r = \sqrt{1^2 + 2^2} = \sqrt{5},\quad \theta = \tan^{-1}(2)
\]
Then,
\[
(1 + 2i)^6 = r^6 \cdot \text{cis}(6\theta) = 5^3 \cdot \text{cis}(6 \tan^{-1}(2))
\]
Evaluate using calculator or De Moivre’s theorem. Result is neither matching any of the options.