In the electrochemical cell :
\(Zn|ZnSO_4(0.01M)||CuSO_4(1.0 M)|Cu,\)
the emf of this Daniel cell is \(E_1\). When the concentration of \(ZnSO_4\) is changed to 1.0 M and that of \(CuSO_4\) changed to 0.01 M, the emf changes to \(E_2\). From the following, which one is the relationship between \(E_1\) and \(E_2\)?
(Given, \(\frac {RT}{F}= 0.059\))