List of top Questions asked in CUET (UG)

Match List I with List II

Choose the correct answer from the options given below:

For the LPP, Min \(Z= 5x + 7y\) subject to \(x≥0, y≥0; 2x+y≥8, x+2y≥ 10,\) the basic feasible solutions are:

If |\(\vec{a}\)| = 5, |\(\vec{b}\)| = 2 and |\(\vec{a}\) · \(\vec{b}\) | = 8 then the value of |\(\vec{a} \)×\(\vec{b} \)| is:

If\(|\vec {a}+\vec {b}|=15, |\vec {a}-\vec{b}| =10,|\vec a|=\frac{11}{2}\) then the value of |\(\vec b\)| is/are:

The angle between the straight lines \(\frac{x+4}{2}=\frac{y+5}{5}=\frac{z+6}{3} \space and \space \frac{x-4}{10}=\frac{y-5}{2}=\frac{z-6}{-10}\) is.

The direction ratios of the line perpendicular to the lines \(\frac{x-7}{-6}= \frac{y+17}{4}= \frac{z-6}{2} \space and \space \frac {x+5}{6}=\frac{y+3}{3}=\frac{z-4}{-6}\) are proportional to:

The integrating factor of \(sinx \frac{dy}{dx}+2ycosx=4\) is:

The maximum value of Z= 2x + 3y subject to the constraints x≥0, y>0; x+y≤ 10, 3x+4y≤ 36 is:

The solution of the differential equation \(\frac{dy}{dx}=-\frac{x}{y}\) is:

Area lying between the curves \(y^2 = 9x\) and y = 3x is:

Area lying in first quadrant and bounded by the circle \(x^2+ y^2 = 9\) and the lines x = 1 and x = 3 is:

The equation of the normal to the curve y = 2sinx at (0, 0) is:

The function \(f(x)= \frac{x^4}{4}-\frac{x^2}{2}\) has

The value of \(\int\limits_{-1}^1x^2 [x] dx\) is:

The value of \(\int\limits_{-3}^2x^2 |2x| dx\) is:

If A=(2, 3), B = (-1, 0), C = (4, 6) then area of the parallelogram ABCD is:

The derivative of \(f (cot x)\) with respect to \(g (cosec x)\) at \(x=\frac{π}{4}\) (where \(f'(1)=2.g'(\sqrt2)=4\)) is:

If \(x = e^{y+e^y+.... to \space ∞}, x> 0\) then \(\frac{d^2y}{dx^2}\) is:

The value of the determinant \(\begin{vmatrix}cos^2θ&cosθsinθ&0 \\-sinθ&cosθ&0 \\ 0&0&1 \end{vmatrix}\) is equal to

The values of b for which the function f(x) = cos x + bx+ a decreases on R are

Let\[f(x)=\begin{cases} 2x-1, x<1\\ 1, x=1 \\ x^2,x>1 \end{cases}\]then at x = 1

If \(A= \begin{bmatrix}1&√3&0 \\-√3&1&0 \\ 0&0&2 \end{bmatrix}\) and \(B=\begin{bmatrix}√3&1&0 \\-1&√3&0 \\ 0&0&2 \end{bmatrix}\) then AB is equal to :

If A=\(\begin{bmatrix} 2&3 \\ -1&1\end{bmatrix}\)and \(A^2-3A+kI = 0\) then the value of k is:

If the matrix \(\begin {bmatrix} x-y&1&-2 \\ 2x-y&0&3 \\ 2&-3&0 \end {bmatrix}\) is skew-symmetric, then values of x and y are respectively

The value of tan(cos^-1x) is: